n-3/n+3+1/n-3=18/n^2-9

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Solution for n-3/n+3+1/n-3=18/n^2-9 equation:


D( n )

n = 0

n^2 = 0

n = 0

n = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

n-(3/n)+1/n-3+3 = 18/(n^2)-9 // - 18/(n^2)-9

n-(3/n)+1/n-(18/(n^2))-3+3+9 = 0

n-3*n^-1+1/n-18*n^-2-3+3+9 = 0

1*n^1-2*n^-1-18*n^-2+9*n^0 = 0

(1*n^3+9*n^2-2*n^1-18*n^0)/(n^2) = 0 // * n^4

n^2*(1*n^3+9*n^2-2*n^1-18*n^0) = 0

n^2

n^3+9*n^2-2*n-18 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6, 9, -9, 18, -18 }

1

n = 1

n^3+9*n^2-2*n-18 = -10

1

-1

n = -1

n^3+9*n^2-2*n-18 = -8

-1

2

n = 2

n^3+9*n^2-2*n-18 = 22

2

-2

n = -2

n^3+9*n^2-2*n-18 = 14

-2

3

n = 3

n^3+9*n^2-2*n-18 = 84

3

-3

n = -3

n^3+9*n^2-2*n-18 = 42

-3

6

n = 6

n^3+9*n^2-2*n-18 = 510

6

-6

n = -6

n^3+9*n^2-2*n-18 = 102

-6

9

n = 9

n^3+9*n^2-2*n-18 = 1422

9

-9

n = -9

n^3+9*n^2-2*n-18 = 0

-9

n+9

n^2-2

n^3+9*n^2-2*n-18

n+9

-n^3-9*n^2

-2*n-18

2*n+18

0

n^2-2 = 0

DELTA = 0^2-(-2*1*4)

DELTA = 8

DELTA > 0

n = (8^(1/2)+0)/(1*2) or n = (0-8^(1/2))/(1*2)

n = 2^(1/2) or n = -2^(1/2)

n in { -2^(1/2), 2^(1/2), -9}

n in { -2^(1/2), 2^(1/2), -9 }

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